A patient has just spontaneously ruptured her membranes. Which of the following factors makes her especially high risk for having a prolapsed cord? Select all that apply.
Occiput anterior position.
Breech presentation.
Cervical dilation 5 cm.
Station-4.
Correct Answer : B,D
A. Occiput anterior position. The occiput anterior (OA) position is the ideal fetal position for vaginal delivery, where the baby’s head is well-engaged in the pelvis. This positioning reduces the risk of a prolapsed cord since the presenting part (the fetal head) effectively blocks the cord from slipping through.
B. Breech presentation. In a breech presentation, the buttocks or feet are the presenting part, leaving more space in the birth canal. This increases the risk of cord prolapse, especially if the feet or buttocks do not fully block the cervix, allowing the umbilical cord to slip past and become compressed.
C. Cervical dilation 5 cm. While cervical dilation is important in labor progression, it does not directly increase the risk of cord prolapse. The risk is more dependent on fetal position and station rather than the degree of cervical dilation.
D. Station -4. A high fetal station (e.g., -4) means the baby’s presenting part has not yet descended into the pelvis, leaving more room for the umbilical cord to slip through once the membranes rupture. A well-engaged fetus at station 0 or lower helps prevent prolapse by blocking the cervix.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
A. Jaundice. Oxytocin does not cause jaundice in the mother. Jaundice is typically related to liver dysfunction, hemolysis, or bile obstruction and is not an expected side effect of oxytocin administration.
B. Dehydration. While prolonged labor induction may contribute to dehydration if fluid intake is insufficient, oxytocin itself does not directly cause dehydration. IV fluids are typically administered alongside oxytocin to maintain hydration during labor.
C. Uterine hyperstimulation. Uterine hyperstimulation (tachysystole), defined as more than five contractions in 10 minutes, is a serious complication of oxytocin administration. It can lead to fetal distress, uterine rupture, and impaired placental perfusion. If hyperstimulation occurs, the nurse should discontinue oxytocin, reposition the patient, provide oxygen, and notify the provider.
D. Maternal bradycardia. Oxytocin does not typically cause bradycardia. Maternal side effects are more commonly tachycardia, hypertension, or fluid retention. Fetal bradycardia, however, can occur if uterine hyperstimulation leads to fetal hypoxia.
Correct Answer is A
Explanation
A. Perform vaginal exam and apply upward digital pressure to the presenting part. A prolapsed umbilical cord is an obstetric emergency that can lead to cord compression and fetal hypoxia. The priority intervention is for the nurse to manually lift the presenting part (usually the fetal head) off the cord to relieve pressure and restore blood flow. The nurse should maintain this position until an emergency cesarean section is performed.
B. Immediately turn the client to her side. Positioning changes, such as the knee-chest or Trendelenburg position, can help relieve pressure on the cord, but they are secondary to manually lifting the presenting part. While turning the client may assist, it is not the most immediate life-saving action.
C. Call the physician immediately. While notifying the provider is essential, relieving pressure on the umbilical cord takes priority. Delaying intervention to make a call could result in prolonged fetal hypoxia and compromise.
D. Place a moist, clean towel over the cord to prevent drying. Covering the cord with a moist towel helps prevent vasospasm and drying, but it does not relieve the compression that is cutting off oxygen to the fetus. The priority is to relieve pressure on the cord first before taking other measures.
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