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Exhibits

The nurse should place the client in a

position to promote

Answer and Explanation

The Correct Answer is {"dropdown-group-1":"B","dropdown-group-2":"C"}

Semi Fowler's position:

-    This position involves raising the head of the bed to an angle of 30 to 45 degrees. It is

commonly used to improve respiratory function and comfort in patients who are experiencing
 
difficulty breathing. By elevating the head and torso, this position facilitates better lung expansion, helping to improve oxygenation.


Promote lung expansion:

-    In patients with respiratory issues such as pneumonia, positioning that enhances lung expansion is critical. Semi Fowler's position helps to reduce pressure on the diaphragm, allowing for more effective lung expansion and improved oxygenation. This is particularly important for a patient with decreased breath sounds and consolidation in the lungs, as it aids in alleviating respiratory distress and improving gas exchange.


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Related Questions

Correct Answer is C

Explanation

A. BRCA1 and BRCA2 provide protection of mature, functioning breast and ovarian cells. This is not accurate; BRCA1 and BRCA2 genes are involved in DNA repair, and mutations in these genes increase cancer risk.
B. The choice of treatment is best determined by the sensitivity of these genetic markers. While genetic markers can influence treatment decisions, this option does not directly address the role of BRCA1 and BRCA2 mutations in cancer risk.
C. Mutations in BRCA1 or BRCA2 identify a client's risk for cancerous cell development in breast tissue. This is correct. Mutations in these genes significantly increase the risk of developing breast and ovarian cancer.
D. The prognosis of breast cancer is most successful when these markers are inherited mutations.
This statement is incorrect. The presence of BRCA1 or BRCA2 mutations influences risk, not necessarily prognosis or treatment success.

Correct Answer is ["0.2"]

Explanation

Step-by-step Calculation:

  1. We need to find the volume (in mL) of teriparatide that contains the desired dose of 60 mcg.
  2. Set up the proportion:dose (mcg) / concentration (mcg/mL) = volume (mL)
  3. Fill in the known values:
    • Dose (mcg): 60 mcg (as given in the problem)
    • Concentration (mcg/mL): 750 mcg/2.4 mL (from the medication label)
  4. Solve for the volume:
    • Multiply both sides of the proportion by the concentration to isolate the volume on the left:
    • dose (mcg) = volume (mL) concentration (mcg/mL)
    • Substitute the known values:
    • 60 mcg = volume (mL) (750 mcg / 2.4 mL)
  5. Calculate the volume:
    • Divide both sides by the concentration to solve for the volume:
    • volume (mL) = 60 mcg / (750 mcg / 2.4 mL)
    • Simplify:
    • volume (mL) = (60 mcg 2.4 mL) / 750 mcg
    • volume (mL) = 0.192 mL (approximately)
  7. Rounding (optional): The problem specifies rounding to the nearest tenth. Since 0.192 is closer to 0.2 than 0.1, the rounded volume is:
  8. volume (mL) = 0.2 mL (rounded to one decimal place)

Therefore, the nurse should administer 0.2 mL of teriparatide.

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