A 6-year-old with a fractured femur is in Russell’s traction. Surgical intervention to correct the fracture is scheduled for the morning. Nursing actions should include which action?
Releasing traction every hour to perform skin care.
Releasing traction once every 8 hours to check circulation.
Maintaining continuous traction until 1 hour before the scheduled surgery.
Maintaining continuous traction and checking the position of traction.
The Correct Answer is D
Choice A reason:
Releasing traction every hour to perform skin care: Releasing traction every hour is not recommended as it can disrupt the alignment and healing process of the fractured femur. Skin care is important, but it should be performed without compromising the traction setup.
Choice B Reason:
Releasing traction once every 8 hours to check circulation: While checking circulation is crucial, releasing traction every 8 hours is not necessary and can interfere with the therapeutic benefits of traction. Circulation can be monitored without releasing the traction.
Choice C Reason:
Maintaining continuous traction until 1 hour before the scheduled surgery: Continuous traction is essential to maintain the alignment of the fractured femur. However, there is no need to release traction 1 hour before surgery unless specifically instructed by the surgical team.
Choice D Reason:
Maintaining continuous traction and checking the position of traction: This is the most appropriate action. Continuous traction ensures proper alignment and healing of the fractured femur. Regularly checking the position of traction helps prevent complications and ensures the effectiveness of the treatment.

Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["2"]
Explanation
Calculation Steps
Step 1: Determine the total urine output in mL.
- Total urine output = 360 mL
Step 2: Determine the child’s weight in kg.
- Weight = 15 kg
Step 3: Determine the time period in hours.
- Time = 12 hours
Step 4: Calculate the urine output in mL/kg/hour.
- Urine output (mL/kg/hour) = Total urine output ÷ (Weight × Time)
Step 5: Perform the multiplication inside the parentheses first.
- Weight × Time = 15 kg × 12 hours = 180 kg·hours
Step 6: Perform the division.
- Urine output (mL/kg/hour) = 360 mL ÷ 180 kg·hours = 2 mL/kg/hour
Result
The child’s urine output is 2 mL/kg/hour.
Correct Answer is D
Explanation
Choice A reason:
Infants do not outgrow clubfoot when they learn to walk. Clubfoot is a congenital deformity that requires medical intervention to correct. Without treatment, the condition can lead to significant disability and difficulty in walking1. The goal of treatment is to correct the foot’s position and function, allowing the child to walk normally.
Choice B reason:
Surgical intervention is not the first line of treatment for clubfoot. While surgery may be necessary in severe cases or if other treatments fail, the initial approach typically involves non-surgical methods. The Ponseti method, which includes serial casting and gentle manipulation, is the preferred initial treatment. Surgery is considered only if these methods do not achieve the desired results.
Choice C reason:
Traction with foot manipulation is not a standard treatment for clubfoot. The primary non-surgical treatment involves the Ponseti method, which includes serial casting and gentle manipulation of the foot3. This method has been shown to be highly effective in correcting clubfoot without the need for traction.
Choice D reason:
Frequent serial casting is the first line of treatment for clubfoot. The Ponseti method, which involves weekly casting and gentle manipulation of the foot, is the most widely used and effective treatment for clubfoot. This method gradually corrects the foot’s position over several weeks, followed by bracing to maintain the correction4. Serial casting is preferred because it is non-invasive and has a high success rate.
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