The nurse is caring for an infant with developmental dysplasia of the hip. Which clinical manifestations would the nurse expect to observe? (Select all that apply.)
Positive Ortolani click
Unequal gluteal folds
Trendelenburg sign
Negative Babinski sign
Telescoping of the affected limb
Correct Answer : A,B,C,E
The correct answer is a) Positive Ortolani click, b) Unequal gluteal folds, c) Trendelenburg sign, and e) Telescoping of the affected limb.
Choice A reason:
A positive Ortolani click is a clinical manifestation of developmental dysplasia of the hip (DDH). The Ortolani maneuver is used to detect hip dislocation or subluxation in infants. When the hip is abducted and gentle pressure is applied to the proximal thigh from behind, a palpable “clunk” is noticed as the femoral head relocates into the acetabulum. This indicates hip instability, which is a characteristic of DDH.
Choice B reason:
Unequal gluteal folds are another clinical manifestation of DDH. Asymmetrical gluteal creases can suggest hip dysplasia in infants. This is because the dislocation or subluxation of the hip can cause one leg to appear shorter than the other, leading to uneven gluteal folds.
Choice C reason:
The Trendelenburg sign is a clinical test used to assess the integrity and strength of the hip abductor muscles, particularly the gluteus medius and gluteus minimus. A positive Trendelenburg sign usually indicates weakness in these muscles, which can be associated with hip abnormalities such as congenital hip dislocation3. In DDH, the hip instability can lead to a positive Trendelenburg sign.
Choice D reason:
A negative Babinski sign is not a clinical manifestation of DDH. The Babinski reflex is a normal reflex in infants up to 2 years old, where the big toe moves upward and the other toes fan out when the sole of the foot is stroked. A negative Babinski sign would indicate the absence of this reflex, which is not related to DDH.
Choice E reason:
Telescoping of the affected limb is a clinical manifestation of DDH. In a child with DDH, the hip socket is shallow, and the head of the femur may slip in and out, leading to a telescoping effect. This means the femoral head can move further out of the socket, causing the limb to appear shorter or longer depending on the position.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is D
Explanation
Choice A reason:
Bacteriuria, or the presence of bacteria in the urine, is not a primary clinical manifestation of acute renal failure. While facial edema can occur due to fluid retention, bacteriuria is more commonly associated with urinary tract infections. Acute renal failure primarily affects the kidneys’ ability to filter waste and regulate fluid and electrolytes, leading to symptoms such as oliguria and hypertension.
Choice B reason:
Hematuria, or blood in the urine, can be a symptom of various kidney conditions, but it is not a primary manifestation of acute renal failure1. Pallor, or paleness, can occur due to anemia, which may be a secondary complication of chronic kidney disease rather than acute renal failure. The primary symptoms of acute renal failure are related to the sudden decline in kidney function, such as oliguria and hypertension.
Choice C reason:
Proteinuria, or the presence of excess protein in the urine, is more commonly associated with chronic kidney disease or nephrotic syndrome rather than acute renal failure. Muscle cramps can occur due to electrolyte imbalances, but they are not primary manifestations of acute renal failure. The primary symptoms of acute renal failure include oliguria and hypertension.
Choice D reason:
Oliguria, or reduced urine output, and hypertension, or high blood pressure, are primary clinical manifestations of acute renal failure. Acute renal failure results in a sudden decline in kidney function, leading to the retention of waste products and fluids, which can cause oliguria and hypertension. These symptoms are key indicators of acute renal failure and require prompt medical attention.
Correct Answer is B
Explanation
The correct answer is b. 25%.
Choice A: 50%
If both parents are heterozygous for the sickle cell trait (carriers), each child has a 50% chance of inheriting one sickle cell gene from one parent and a normal gene from the other parent. This would make the child a carrier of the sickle cell trait, not someone with sickle cell anemia. Therefore, the chance of having sickle cell anemia is not 50%.
Choice B: 25%
When both parents are carriers of the sickle cell trait (heterozygous), there is a 25% chance that their child will inherit two sickle cell genes (one from each parent), resulting in sickle cell anemia. This is because each parent has one normal hemoglobin gene (A) and one sickle cell gene (S). The possible combinations for their children are AA (normal), AS (carrier), SA (carrier), and SS (sickle cell anemia). The probability of the SS combination is 25%.
Choice C: 75%
A 75% chance is not accurate in this scenario. The 75% figure might be mistakenly considered if one were to add the probabilities of being a carrier (50%) and having sickle cell anemia (25%). However, these probabilities are distinct and should not be combined in this manner.
Choice D: 100%
A 100% chance would imply that every child of the couple would have sickle cell anemia, which is not the case. Since each parent is a carrier, there is only a 25% chance for each child to have sickle cell anemia. The remaining 75% of the time, the child will either be a carrier or have normal hemoglobin.
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