Sodium and water accumulation in an injured cell are a direct result of:

Choice A Reason:

Atrophy refers to the reduction in size or wasting away of an organ or tissue due to a decrease in cell size or number. It is not a type of cell death but rather a process of cell shrinkage and loss of function. Therefore, it does not directly relate to the damage caused to nearby cells.

Choice B Reason:

This is the correct answer. Apoptosis is a form of programmed cell death that occurs in a controlled and regulated manner. It allows for the removal of damaged or unnecessary cells without causing an inflammatory response or damage to surrounding tissues. During apoptosis, cellular components are neatly packaged into vesicles called apoptotic bodies, which are then phagocytosed by neighboring cells or immune cells, preventing the release of harmful substances.

Choice C Reason:

Necrosis is a form of traumatic cell death that results from acute cellular injury. It often leads to the uncontrolled release of cellular contents, causing inflammation and damage to surrounding tissues. This process can be detrimental to nearby cells and is generally considered more harmful than apoptosis.

Choice D Reason:

Lysis refers to the breaking down or destruction of cells, often due to external factors such as toxins, infections, or immune responses. Like necrosis, lysis can result in the release of cellular contents into the surrounding environment, leading to inflammation and damage to nearby cells.

Choice A Reason:

The statement that the medication will be completely out of the patient’s body after three days is incorrect. The half-life of a drug indicates the time it takes for the concentration of the drug in the body to reduce by half. After one half-life (one day), 50% of the drug remains. After two half-lives (two days), 25% remains. After three half-lives (three days), 12.5% remains. Therefore, some amount of the drug will still be present in the body after three days.

Choice B Reason:

To calculate the amount of medication remaining after three days, we use the half-life formula. Starting with 10 mg, after one day (one half-life), 5 mg remains. After two days (two half-lives), 2.5 mg remains. After three days (three half-lives), 1.25 mg remains. This calculation shows that 1.25 mg of the medication will still be in the patient’s body after three days.

Choice C Reason:

The choice of 5 mg is incorrect because it represents the amount of medication remaining after one half-life (one day), not three half-lives. After one day, 50% of the initial dose remains, which is 5 mg. However, the question asks for the amount remaining after three days.

Choice D Reason:

The choice of 1 mg is also incorrect. After three half-lives, the amount of medication remaining is 12.5% of the initial dose. For an initial dose of 10 mg, this would be 1.25 mg, not 1 mg. The calculation must accurately reflect the reduction by half for each half-life period.